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1/2x^2=648
We move all terms to the left:
1/2x^2-(648)=0
Domain of the equation: 2x^2!=0We multiply all the terms by the denominator
x^2!=0/2
x^2!=√0
x!=0
x∈R
-648*2x^2+1=0
Wy multiply elements
-1296x^2+1=0
a = -1296; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-1296)·1
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*-1296}=\frac{-72}{-2592} =1/36 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*-1296}=\frac{72}{-2592} =-1/36 $
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